Answer:
No solution
Explanation:
Given inequality:
![3+4x \leq 2(1+2x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/woh4r30fecn46wr3lvkpnrg3nyhgq226dg.png)
To determine if the given inequality has a solution, we can solve it step by step.
Begin by expanding the brackets on the right side of the inequality:
![3+4x\leq 2\cdot 1+2\cdot 2x](https://img.qammunity.org/2023/formulas/mathematics/high-school/osroughla1h2b9n5z45sxycigrf505gcpb.png)
![3+4x \leq 2+4x](https://img.qammunity.org/2023/formulas/mathematics/high-school/hmheto7wdn6pheqhjc0ftt8852njf60i1m.png)
Now, subtract 4x from both sides to isolate the constant terms:
![3+4x-4x \leq 2+4x-4x](https://img.qammunity.org/2023/formulas/mathematics/high-school/o2t0gjprc536mi1lhv1wq8k5kgieuc4uhw.png)
![3 \leq 2](https://img.qammunity.org/2023/formulas/mathematics/high-school/f8iene1hdhezha8la2erqofdxduz85jj2p.png)
As 3 is not less than or equal to 2, there is no solution to the inequality since the inequality has led to a contradiction.
Therefore, the two sides of the inequality will never be equal or allow for 3 + 4x to be less than 2(1 + 2x) for any value of x.