Question

A ball of mass 0.440 kg moving with a speed of 3.70 [m / s] collides head-on with a 0.220 [kg] ball at rest. If the 0.440 [kg] ball moves at 1.23 [m / s] in its original direction, what is the speed of the 0.220 [kg] ball after the collision?

Answer 1

Answer: 3.0 m/s

Step-by-step explanation:

Conservation of momentum: total momentum before collision = total momentum after collision

momentum = p = mv

(0.440 kg)(3.70 m/s) + (0.220 kg)(0.0 m/s) = (0.440 kg)(1.23 m/s) + (0.220 kg)(x)

Solve for x, speed of the 0.220 kg ball after the collision:

1.628 + 0 = 0.54x

x = 1.628/.54 = 3.0 m/s