Final answer:
Electron-dot notation shows Li losing one electron to form Li+, and Cl gaining one electron to form Cl-, combining to form LiCl. Similarly, Ca loses two electrons to form Ca2+, and two I atoms each gain one electron to form I-, resulting in CaI2. Other pairs of ions mentioned form compounds like copper(II) fluoride (CuF2) and calcium oxide (CaO).
Step-by-step explanation:
To use electron-dot notation to demonstrate the formation of ionic compounds, we'll consider the transfer of electrons between atoms to form ions that combine to produce a neutral compound. For the pair Li (lithium) and Cl (chlorine), lithium (with one valence electron) will lose its electron to become Li+, while chlorine (with seven valence electrons) will gain an electron to become Cl-. The resulting ionic compound is lithium chloride, with the formula LiCl.
For the pair Ca (calcium) and I (iodine), calcium (with two valence electrons) will lose two electrons to become Ca2+, while each iodine atom (also with seven valence electrons) will gain one electron to become I-. Two iodine ions are needed to balance the charge of one calcium ion, resulting in the compound calcium iodide with the formula CaI2.
Additional information involves giving formulas and names for ionic compounds formed between different pairs of ions, such as Cu2+ and F- resulting in copper(II) fluoride, Ca2+ and O2- resulting in calcium oxide, and formulas for compounds like Li2S (lithium sulfide) and CaO (calcium oxide).