Question

The table shows data about lightning and thunder.

Lightning and Thunder Data
Occurrence Lightning
Observed Thunder Heard Distance to
Lightning (m)
A 8:00:00 p.m. 8:00:01 p.m. 330
B 5:30:00 p.m. 5:30:04 p.m. 1,320
C 6:45:00 p.m. 6:45:06 p.m. 1,980
D 7:20:00 p.m. 7:21:00 p.m. 19,800

According to the table, how fast does the sound of thunder travel?

Answer 1

Step-by-step explanation:

If the question is set up correctly here, we can solve this correctly.

Lightning and Thunder Data

Occurrence Lightning

Observed Thunder Heard Distance to ---- We need this

Lightning (m)

A 8:00:00 p.m. 8:00:01 p.m. 330

B 5:30:00 p.m. 5:30:04 p.m. 1,320

C 6:45:00 p.m. 6:45:06 p.m. 1,980 ---- We need this

D 7:20:00 p.m. 7:21:00 p.m. 19,800

6:45:06 - 6:45:00 = 6

So 6 seconds. We also get 1980. So we do 1980/6, which is 330(m)?

If the unit is meters, then the sound of thunder travels at 330(m)