Question

At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant

Answer 1

Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer

answer : mass of Bananas ( m ) =
`(A^2)/(V^2) * K`

To calculate for weight of Bananas = m * g where g = 9.8

Step-by-step explanation:

Given an amplitude ( A )= 29.8981

Spring constant = x ( unknown )

maximum speed of Bananas( v ) = wA ( unknown )

question : calculate the weight of the bananas

First step : calculate the period of oscillation

T =
`(2\pi )/(vA)` --- ( 1 )

next step : express T in terms of mass ( m ) of the bananas

=
`2\pi \sqrt{(m)/(k) } = (2\pi )/(vA)`

∴ m/k = A^2 / v^2

hence mass of Bananas ( m ) =
`(A^2)/(V^2) * K`

To calculate for weight = m * g