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27 votes
27 votes
A 33 gram sample of a substance that's

used for drug research has a k-value of
0.1124.

Find the substances half life and the round your answer to the nearest 10th

User Andrew Shore
by
2.8k points

1 Answer

13 votes
13 votes

9514 1404 393

Answer:

6.2

Explanation:

We presume your "k-value" is the k in the exponential decay term ...

e^(-kt) . . . where t is the number of time units

This is 1/2 when ...

ln(1/2) = -kt

t = ln(1/2)/(-k) = ln(2)/k

t = 0.69315/0.1124 ≈ 6.2

The half life is about 6.2 time units.

User DeltaLima
by
3.2k points