Question

A company logo

is shaped like an equilateral triangle with
2-in.-long sides. What is the height of the
logo? Round to the nearest tenth.

Answer 1

`\textit{height of an equilateral triangle}\\\\ h=\cfrac{s√(3)}{2} ~~ \begin{cases} s=sides\\[-0.5em] \hrulefill\\ s=2 \end{cases}\implies h=\cfrac{2√(3)}{2}\implies h=√(3)\implies h\approx 1.7`