Question

Could you help me with this maths question? Tysm

Answer 1

Hi! I will help you with a smile! :)

• Recall the Properties of Exponents:
• 
  `\bold{a^(m) *a^n =a^(m+n)}`
• Now, let's use this property to solve our problem:
• 
  `\displaystyle(j)/(j^(4) *j)`
• 
  `\displaystyle(j)/(j^(4+1) )`
• 
  `\displaystyle(j)/(j^(5) )`
• Now, here comes the 2nd Property of Exponents:
• 
  `\displaystyle(a^(m) )/(a^(n) ) =a^(m-n)`
• Let's use this property to solve our problem:
• 
  `\displaystyle(j)/(j^(5) ) =j^(1-5)`
• Think of j as j to the first power.
• Now, subtract the exponents:
• 
  `\bold{j^(-4)}`

Answer:

`\huge\boxed{j^(-4) }}\checkmark`

Hope it helps.

Please comment if you have any doubts.

Answered by

`\fbox{PeacefulNature}`

`\text{Enjoy Your Day, Evening, or Night!}`

Answer 2

The correct answer is: "
`j^(^-^4^)` "; or; write as: "
`j^(-4)` ".

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Explanation:

Given: "
`(j)/(j^4* j)` " ; assuming: "
`j\\eq 0` " ;
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We are asked to express the correct answer (i.e. simplying the expression in a specific manner): "as a single term, without a denominator."
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As such, we can cancel out the "j" in the numerator, to "1" ; and cancel out the "j" in the denominator; to "1" ; since: " j ÷ j = 1 " ;

→ And we can rewrite the expression as:
"
`(1)/(j^(4)* 1 )` " ;

= "
`(1)/(j^4)` " ;
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Now, note the following property of exponents:
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"
`x`⁽⁻ⁿ⁾ =
`(1)/(x^n)` " ; {"
`x\\eq 0` "} ;
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Likewise:
"
`(1)/(j^4)` ⇔ "
`j^(^-^4^)` " ; which is the correct answer:

→ "
`(1)/(j^4) = j^(-4)` " .
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Hope this is helpful to you!
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