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disregarding air resistance, what is the speed of a ball dropped from 12 feet just before it hits the ground? (use 1 ft

User Zeroliu
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Answer: Since the ball is free-falling, you use this equation:

v^2 = 2gh

where v is the velocity

g is the acceleration due to gravity

h is the height at which the object is dropped from

Plugging in the values and converting ft to m,

v^2 = 2 (9.8) (12) (0.3)

v = 8.4 m/s

User Hassan Saeed
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