Question

the length of a rectangle is four times its width. if the perimeter is at most 130 centimeters, what is the greatest possible value for the width? question 3 options: 2w + 2 • (4w) < 130 2w + 2 • (4w) > 130 2w + 2 • (4w) ≤ 130 2w + 2 • (4w) ≥ 130

Answer 1

Explanation:

Let L be the Length and W be the Width of a rectangle.

We are told that: L = 4W [the length of a rectangle is four times its width]

Perimeter = 2L + 2W

We learn that P ≤ 130 cm

2L + 2W ≤ 130 cm

Substitute L = 4W:

2L + 2W ≤ 130 cm

2(4W) + 2W ≤ 130 cm

10W ≤ 130 cm

W ≤ 13 cm

Options:

2w + 2 • (4w) < 130 Not correct since the < sign does not allow for the "at most 130 cm.")

2w + 2 • (4w) > 130 Must be ≤, not >

2w + 2 • (4w) ≤ 130 This option works since the ≤ sign is correct.