Question

If 45.0 mL of a 6.0 M HCI solution are dilute with pure water to a volume of 1.0 L , what is the concentration of the resulting solution?

Answer 1

Answer: 0.27 M

Step-by-step explanation:

c1V1=c2V2

c1=6.0 M;V1=45.0 mL

c2=?;V2=1.0 L=1000 mL

c2=(c1V1)/V2

c2=((6.0)(45.0))/1000

c2=0.27 M