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How many moles of CaCl₂ would there be in 42 mL of 2.09 M aqueous CaCl₂ solution?

3 significant figures

1 Answer

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Answer:

0.0878 moles CaCl₂

Step-by-step explanation:

To find the amount of moles of CaCl₂, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (M = moles / L)

It is important to arrange the conversions in a way that allows for the cancellation of units.

(Step 1)

42 mL CaCl₂ 1 L
------------------------ x ---------------------- = 0.042 L CaCl₂
1,000 mL

(Step 2)

Molarity (M) = moles / volume (L) <----- Molarity ratio

2.09 M = moles / 0.042 L <----- Insert values

0.0878 = moles <----- Multiply both sides by 0.042 L

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