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PLEASE HELP ASAP

Part A: A 30-kilogram mass is moving across a horizontal surface at 5.0 m/s. The mass comes to
a stop over 6 seconds. What is the acceleration?

Part B: What is the magnitude of the force required to bring the object to a stop?

1 Answer

3 votes

Answer:

Below

Explanation:

acceleration = Δv / Δt = - 5/6 m/s^2

( negative sign shows it to be a deceleration)

F = ma

= 30 ( -5/6) = -25 N or 25 N in the direction opposite of the velocity ( like a frictional force)

User Milad Bahmanabadi
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