Question

6. A chemist needs to create 100mL of 38% acid solution. On hand she has a 20% acid solution and

a 50% acid solution. How many mL of each solution should she use?
Solution: 20% acid =
50% acid =

Answer 1

40 cc of A and 60 cc of B

Explanation:

A+B = 100

0.5A + 0.8B = 100 * 0.68 = 68

0.5A + 0.8 ( 100 - A) = 68

0.5A + 80 - 0.8A = 68

-0.3A = -12

3A = 120

A=40

40 cc of A and 60 cc of B