Answer:
n² + 5n is the nth term rule for the sequence
Explanation:
6 14 24 36...
8 10 12 (first difference)
2 2 (second difference)
second difference = 2
now,
here the nth term would be an² + bn + c
Now,
second difference = 2a
or, 2 = 2a
so, a = 1
To solve for b,
if n = 2,
an² + bn + c = 14
or, 2² + b×2 + c = 14
or, 4 + 2b + c = 14
so, 2b + c = 10
so, c = 10 - 2b
Now,
if n = 1,
an² + bn +c = 6
1² + b × 1 + c = 6
or, 1 + b + c = 6
or, b+c = 5
as we know,
c = 10-2b
Now,
b+c = 5
or, b - (10 - 2b) = 5
so, b - 10 + 2b = 5
so, 3b = 15
so, b = 5
now,
c = 10-2b
or, c = 10 - 2×5
so, c = 10-10 = 0
so
an² + bn + c = n² + 5n + 0
so, the nth term = n² + 5n