Question

Solve for x: x^2 + 6√3 x – 9 = 0

Answer 1

Explanation:

use this equation :

if , ax² + bx + c = 0

`x \: = \frac{ - b \: ( + )/( ) \sqrt{ {b}^(2) - 4ac} \: }{2a}`

so here, a = 1

b = 6√3

c = -9

let's use the formula .......

`x \: = \: \frac{ - 6 √(3) \frac{ + }{} √(36 * 3 - 4(1)( - 9)) }{2(1)}`

`x \: = \: \frac{ - 6 √(3) \frac{ + }{} √(108 \: + 36) }{2}`

`x \: = \: \frac{ - 6 √(3) \frac{ + }{} √(144) }{2}`

`x \: = \: \frac{ - 6 √(3) \frac{ + }{} 12 }{2}`

`x \: = \: ( - 6 √(3) + 12 )/(2)`

OR .......

`x \: = \: ( - 6 √(3) - 12 )/(2)`

so , X = -3√3 +6 ............ or

X = -3√3 -6 ............