Haha ITS MATHXL
Anyways, constant rate of +90 and currently has 1560.
Say y will be the amount of students, and x is how many years later.
y=90x+1560
So for a), the answer is y=90x+1560
For b), plug in 3 for x, since 2017 is 3 years after 2014.
y=90(3)+1560
y=270+1560
y=1830
Amount of students in 2017: 1830
For c), plug in 2010 for y.
2010=90x+1560
Subtract 1560 both sides
450=90x
Divide both sides by 90
x=5
Answers
a) y=90x+1560
b) 1830
c) 5 Years Later, or 2019
Hope this helps!