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The action of a waterwheel can be modeled by the function y = 3 cos (π (x-3) + 2).

Within the interval 0 that value?

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Answer:

y = 3 cos (π (0-3) + 2)

y = 3 cos (-2π + 2)

y = 3 cos (-2)

y = 3(-1)

y = -3

User Yashwanth Kumar
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