27.9k views
7 votes
....................​

....................​-example-1

1 Answer

9 votes

Answer:


\boxed{\large\sf y = 3x - 5}

Explanation:

Here we are given a equation which is ,


\longrightarrow y = 3x + 6

We need to find out the equation of the line which is parallel to the given line and passes through the given point .

  • And as we know that the slope of two parallel lines are equal .

On comparing the given equation with slope intercept form (y = mx + c )of the line , we have ,


\longrightarrow m = 3

Therefore the slope of the parallel line will be ,


\longrightarrow m_(||)= 3

Now we can use the point slope form of the line which is ,


\longrightarrow y - y_1 = m(x - x_1)

Substitute ,


\longrightarrow y - 7 = 3 ( x -4)\\\\\longrightarrow y -7 = 3x -12 \\\\\longrightarrow y = 3x -12+7\\\\\longrightarrow y = 3x -5

This is the required answer .

User Shadowtrot
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.