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If exactly one molecule of solute is present in 1. 00 l of solution, what is the concentration of the solution?.

User Kunjal
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1 Answer

6 votes

Answer:

1.66x10^-24 M

Step-by-step explanation:

By definition, 1 mole = 6.02x10^23 particles, or molecules, in this case. Use this relationship as a conversion factor:

((1 mole)/(6.02x10^23 molecules))

Use this conversion factor to calculate moles of the solute when only 1 molecule is present:

(1 molecule)/((1 mole)/(6.02x10^23 molecules)) = 1.66x10^-24 moles

The molecules cancel, leaving only moles.

Concentration, by definition, is the moles per liter of a solute. Take the

1.66x10^-24 moles and divide by the volume, which is 1.0L here:

(1.66x10^-24 moles solute)/(1.0 Liter) = 1.66x10^-24 molar, or 1.66x10^-24 M

User Exan
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