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22 votes
22 votes
There is a bell at the top of a tower that is 45 m high. The bell weighs 190 kg. The bell has

energy. Calculate it

User Sourabh Banka
by
2.4k points

2 Answers

20 votes
20 votes

Answer:

200,000J

Step-by-step explanation:

KE= 0.5 x m x v^2

KE= 0.5x1000x20^2

KE= 0.5 x 1000 x 400

KE= 500 x 400

KE= 200,000

User Liam Haworth
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3.0k points
11 votes
11 votes

Answer: The bell has 8550 J energy.

given, There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N

i.e., bell is located at the top of tower, h = 45m

weight of the bell, F = 190 N

workdone by the gravitational force = F.hcos180°

[ gravitational force (i.e., weight ) acting downward while body is located 45m above the ground. so, angle between force and h = 180° ]

workdone by the gravitational force = 190 × 45 × (-1)

= -8550 J

we know, potential energy = negative of workdone

= -(-8550 J) = 8550 J

User James Moessis
by
3.2k points