Question

Given L(-6, -7) and M(3, 6), what is the length of LM to the nearest tenth?
LM

Answer 1

LM ≈ 15.8

Explanation:

calculate the length d using the distance formula

d =
`}\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = L (- 6, - 7 ) and (x₂, y₂ ) = M (3, 6 )

LM =
`√((3-(-6))^2+(6-(-7))^2)`

=
`√((3+6)^2+(6+7)^2)`

=
`√(9^2+13^2)`

=
`√(81+169)`

=
`√(250)`

≈ 15.8 ( to the nearest tenth )