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A lead block, initially at 58.5oC, is submerged into 100.0 g of water at 24.8oC, in an insulated container. The final temperature of the mixture upon reaching equilibrium is 26.2oC. What is the mass of the lead block?

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Answer:

The specific heat capacity of lead is 0.128 J/g°C.

Mass of lead block = (100.0 g)(26.2oC - 24.8oC)(0.128 J/g°C) / (58.5oC - 24.8oC)

Mass of lead block = 5.45 g

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