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Find the Gradient of the line drawn below.

Find the Gradient of the line drawn below.-example-1
User Somejkuser
by
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2 Answers

5 votes

Answer:

3 ,0

Explanation:

In vector calculus, the gradient of a scalar-valued differentiable function f of several variables is the vector field \\abla f whose value at a point p is the "direction and rate of fastest increase". Wikipedia

User Ladi
by
8.4k points
5 votes

Answer:

1/3

Explanation:

We need two easy-to-read points on grid intersections.

Look at the point on the y-axis. It is (0, 3).

Now go up to the right until you find the next easy-to-read point.

It is (3, 4) which is on a grid intersection.

gradient = run/rise

rise = distance in y (vertical distance)

run = distance in x (horizontal distance)

We start at (0, 3) and go to (4, 4) by going only vertically and horizontally.

From (0, 3), go 1 unit up. That is a rise of 1.

Then go 3 units right. That is a run of 3.

gradient = rise/run = 1/3

Answer: 1/3

User Filimonov
by
7.8k points

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