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5 votes
5 votes
13 and 14 pls help :))

13 and 14 pls help :))-example-1
User Steve Whitfield
by
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1 Answer

20 votes
20 votes

Answer:

1st and 2nd options

Explanation:

Using the method of completing the square to obtain standard form

(13)

Rearrange the given equation so x and y terms are together, that is

x² + 24x + y² + 30y + 353 = 0 ( subtract 353 from both sides )

x² + 24x + y² + 30y = - 353

To complete the square

add ( half the coefficients of the x/ y term)² to both sides

x² + 2(12)x + 144 + y² + 2(15)y + 225 = - 353 + 144 + 225

(x + 12)² + (y + 15)² = 16

(x + 12)² + (y + 15)² = 4² ← in standard form

with centre = (- 12, - 15 ) and radius = 4

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(14)

As in number 13

x² - 22x + y² + 16y = - 181

Complete the square

x² + 2(-11)x + 121 + y² + 2(8)y + 64 = - 181 + 121 + 64

(x - 11)² + (y + 8)² = 4

(x - 11)² + (y + 8)² = 2² ← in standard form

with centre = (11, - 8 ) and radius = 2

User Carlon
by
2.9k points
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