Which describes bonding electrons in a polar covalent bond? electrons that are not shared equally electrons that are shared in diatomic molecules electrons that are shared equally

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

TheEye asked Jun 27, 2022

528,750 views

40 votes

Which describes bonding electrons in a polar covalent bond?

electrons that are not shared equally

electrons that are shared in diatomic molecules

electrons that are shared equally

Chemistry
college

TheEye asked Jun 27, 2022

by TheEye

2.7k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

2 Answers

16 votes

Answer:

I think the third one

Step-by-step explanation:

i think

Viktoria answered Jun 29, 2022

by Viktoria

3.2k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

22 votes

Answer:

electrons that are NOT shared equally

Step-by-step explanation:

Shantanu Tomar answered Jul 1, 2022

by Shantanu Tomar

3.4k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

2 Answers

0 Comments

Your comment on this answer:

0 Comments

Your comment on this answer:

Other Questions