Question

How does the rate of a chemical reaction change if the concentration of both reactants increases 4 times?

2NO + O2 → 2 NO2

Answer 1

Answer: The rate will increase 32 times if the concentration of both reactants increases 4 times

Step-by-step explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the reaction :
`2NO+O_2\rightarrow 2NO_2`
`rate=k[NO]^2[O_2]^1`

k= rate constant

order with respect to
`NO_2` = 2

order with respect to
`O_2` = 1

Thus on increasing the concentration of reactants 4 times :

`rate'=k[4* NO]^2[4* O_2]^1`

`rate'=k* 8* 4* [NO]^2* [O_2]^1`

`rate'=32* rate`

Thus rate will increase 32 times if the concentration of both reactants increases 4 times