Answer:
a) For Khalil's purchase
4x + 3y = 11.67.....Equation 1
For Ronda's purchase
8x + y = 12.89......Equation 2
b) A can of soup = x = $2.09
Loaf of bread = y = $1.35
Explanation:
A grocery store is offering a sale on bread and soup. Khalil buys four cans of soup and three
loaves of bread for $11.67. Ronda buys eight cans of soup and one loaf of bread for $12.89.
Homework Help!
Let us represent:
a can of soup = x
Loaf of bread = y
a. Write equations for both Khalil's and Ronda's purchases.
For Khalil's purchase
= Khalil buys four cans of soup and three loaves of bread for $11.67.
4x + 3y = 11.67.....Equation 1
Ronda buys eight cans of soup and one loaf of bread for $12.89.
8x + y = 12.89......Equation 2
b. Solve the system to find the price of one can of soup and the price of one loaf of bread.
We have:
4x + 3y = 11.67.....Equation 1
8x + y = 12.89......Equation 2
y = 12.89 - 8x
We substitute 12.89 - 8x for y in Equation 1
4x + 3(12.89 - 8x) = 11.67
4x + 38.67 - 24x = 11.67
38.67 - 11.67 = 24x - 4x
27 = 20x
x = 27/20
x = 1.35
y = 12.89 - 8x
y = 12.89 - 8 × 1.35
y = 12.89 - 10.8
y = 2.09
Therefore,
Solving for y
a can of soup = x = $2.09
Loaf of bread = y = $1.35