Question

A 7.50 kg bowling ball moving directly east at 6.42 m/s strikes a 1.60 kg bowling pin at rest. After, the pin moves 14.8 m/s at a -47.0° angle. What is the x and y component of the ball’s final velocity?

Answer 1

To find the x and y component of the ball’s final velocity, we need the values of v1 and angle.

Step-by-step explanation:

First, we can calculate the momentum of the bowling ball before the collision using the equation:

Momentum = mass x velocity

So, the momentum of the bowling ball (m1) before the collision is:

m1 = 7.50 kg x 6.42 m/s = 48.15 kg*m/s

After the collision, the final momentum can be calculated using the equation:

Final momentum = (mass of bowling ball x velocity of bowling ball) + (mass of bowling pin x final velocity of bowling pin)

Since the bowling pin was at rest before the collision, its initial velocity is 0 m/s. Let's assume the final velocity of the bowling ball is v1 and the final velocity of the bowling pin is v2.

Final momentum = (7.50 kg x v1) + (1.60 kg x v2)

We know that the bowling pin moves 14.8 m/s at a -47.0° angle. To find the x and y component of the ball's final velocity, we can use trigonometry:

x-component of v1 = v1 x cos(angle)

y-component of v1 = v1 x sin(angle)

Therefore, to find the x and y component of the ball's final velocity, we need the values of v1 and angle.