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Please help im desperate and its a 8th grade question only please

Please help im desperate and its a 8th grade question only please-example-1
User Mauguerra
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1 Answer

3 votes

Answer:

a. 31/6; 33/6; 35/6

b. + 2/6

c. 37/6; 39/6; 41/6

d. 49/6

Explanation:

First we need to find the first three terms.

To do so solve the equations in the boxes.

When dividing by a fraction you multiply by the reciprocal so the equations are now as follows:

2 * 31/12

3 * 11/6

5 * 7/6

Solve these to get

62/12 = 31/6

33/6

35/6

The term to term rule as shown above is adding 2/6 or 1/3.

To find the next three terms in the sequence add 2/6 to the term.

35/6 + 2/6 = 37/6

37/6 + 2/6 = 39/6

39/6 + 2/6 = 41/6.

To find the 10th term you need to write out the arithmetic sequence equation.

an = a1 + (n-1)d

an is the term you want to find and n is the term number in this case that is 10. D is the common difference which in this case is 2/6. Plug these into the equation. A1 is the first term in the equation which in this case is 31/6.

31/6 + (10-1) 2/6

31/6 + (9)2/6

31/6 + 18/6 = 49/6

User Rok
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