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45 votes
45 votes
If you have 384.3 grams of Al(OH)3 how many moles do you have?

User John London
by
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2 Answers

22 votes
22 votes
Answer:
(OH) 3 = 27 + (16 x 3) + (1 x 3) which equals 78
348.3 divides by 78 equals 4.92692
Round up and you get 4.93
Step-by-step explanation:

User Uno Mein Ame
by
3.1k points
6 votes
6 votes

Step-by-step explanation:

no of moles = mass / molar mass

mr of Al ( OH)3 = 27+ (16 × 3) + (1 ×3)

= 78

n = 384.3 / 78

n = 4.92692...

n = 4.93

therefore, no of moles = 4.93

User GeoO
by
2.6k points