Question

the focal length of david's lens is 50 cm . if rebecca stands in front of david at a distance of do and david perceives the position of rebecca at di , what does do equal if the magnification is -0.40?

Answer 1

The focal length of David's lens is 50 cm. The image position of Rebecca, di, can be calculated using the formula m = -di/do. Substituting the given values, we can find that di equals -0.384 cm.

Step-by-step explanation:

Start with the equation for magnification, m = -di/do. Solving for di and inserting the given values yields di = mdo - (0.032) (12 cm) = -0.384 cm.