Question

How many moles would be present in a gas contained in a 100.0 mL vessel at 25.0oC at a pressure of 2.50 atm?

Answer 1

n = 0.0102 mol.

Step-by-step explanation:

Hello there!

In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:

`PV=nRT`

Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:

`n=(PV)/(RT)`

Thereafter, we plug in the aforementioned values to obtain:

`n=(2.50atm*0.1000L)/(0.08206(atm*L)/(mol*K)*298.15K)\\\\n=0.0102mol`

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