Question

PLEASE HELP!!!!! Need answer immediately

Rania redesigned the bottom of one of the Landing pools. the equation that describes the bottom of the redesigned pool is y = 2/5x -60 in this equation y represents the depth of the water and x is the distance a guest lands away from the far wall all measurements are in inches. How deep is the water in the pool where a guest lands in the water 36 inches from the wall?
A. Y=74.4 in
B. Y=38.4 in
C. Y=45.6 in
D. Y=60 in

Answer 1

C. y = 45.6 in

Explanation:

Given equation:

`y=(2)/(5)x-60`

where:

• y is the depth of the water (in inches).
• x is the distance a guest lands away from the far wall (in inches).

If a guest lands 36 inches from the wall, then x = 36.

Substitute x = 36 into the equation:

`\implies y=(2)/(5)(36)-60`

`\implies y=(2 \cdot 36)/(5)-60`

`\implies y=(72)/(5)-60`

`\implies y=14.4-60`

`\implies y=-45.6`

Therefore, the depth of the water is 45.6 inches (since -45.6 inches means it is that distance below the surface).