41.5k views
19 votes
If you have 384.3 grams of Al(OH)3 how many moles do you have?

User Addohm
by
4.2k points

2 Answers

11 votes
Answer:
(OH) 3 = 27 + (16 x 3) + (1 x 3) which equals 78
348.3 divides by 78 equals 4.92692
Round up and you get 4.93
Step-by-step explanation:

User Artella
by
4.4k points
7 votes

Step-by-step explanation:

no of moles = mass / molar mass

mr of Al ( OH)3 = 27+ (16 × 3) + (1 ×3)

= 78

n = 384.3 / 78

n = 4.92692...

n = 4.93

therefore, no of moles = 4.93

User Andrew Swan
by
4.2k points