Question

A homeowner sections off part of her backyard for a vegetable garden. The width of the garden is 4 ft shorter than the length. The perimeter of the garden is 52 ft. What are the dimensions of the garden?​

Answer 1

To find the dimensions of the garden, use the given information to set up an equation. Solve the equation to find the length and width of the garden. The dimensions of the garden are 15 ft by 11 ft.

Step-by-step explanation:

To find the dimensions of the garden, we can set up an equation using the given information. Let L be the length of the garden. According to the problem, the width is 4 ft shorter than the length, so the width can be represented as L-4 ft. The perimeter of a rectangle is given by the formula P = 2(L + W), so we can substitute the values into the equation: 52 = 2(L + (L-4)).

Simplifying the equation, we get 52 = 2(2L - 4), which becomes 52 = 4L - 8. Adding 8 to both sides, we have 60 = 4L, and dividing both sides by 4, we get L = 15. Now we can substitute this value back into the width equation, W = L - 4, and calculate the width: W = 15 - 4 = 11 ft.

Therefore, the dimensions of the garden are 15 ft by 11 ft.

Answer 2

length = 15ft

width = 11ft

Step-by-step explanation:

p = 2L + 2w = 52ft

w = L - 4

Substitute: 2L + 2(L-4) = 52

Simplify and solve:

2L + 2L - 8 = 52

4L - 8 = 52

4L = 60

L = 15

w = 15-4 = 11

Check:

2(15) + 2(11) = 52?

30 + 22 = 52!!!