Answer:
Electric field on the surface of the ball 28 kV/m
Step-by-step explanation:
Given:
R = 15 cm = 0.15 m
q = 7.0·10⁻⁸ C
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E - ?
Electric field on the surface of the ball:
E = k·q / R²
E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m or E = 28 kV/m