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a metal sphere of radius 15 cm has a net charge of 7.0 10-8 c. (a) what is the electric field at the sphere's surface?

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Answer:

Electric field on the surface of the ball 28 kV/m

Step-by-step explanation:

Given:

R = 15 cm = 0.15 m

q = 7.0·10⁻⁸ C

________________

E - ?

Electric field on the surface of the ball:

E = k·q / R²

E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m or E = 28 kV/m

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