Question

how much force should be applied on the piston (radius 0.012 meter ) so that a car of 1500 kg is completely supported by a piston of radius 0.15 meter.

Answer 1

Force = 93 N

Step-by-step explanation:

Given:

m₁ = 1500 kg

R₁ = 0.15 m

R₂ = 0.012 m

g = 9.8 m/s²

_____________

F₂ - ?

1)

Piston area:

S₁ = π·R₁² = 3.14·0.15² ≈ 71·10⁻³ m²

S₂ = π·R₂² = 3.14·0.012² ≈ 0.45·10⁻³ m²

2)

Force:

F₁ = m₁·g = 1500·9.8 = 14 700 N

F₂ = F₁· (S₂ / S₁)

F₂ = 14 700· (0.45·10⁻³ / (71·10⁻³) ≈ 93 N