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If point A(-5, -7) lies on the terminal arm of an angle, determine the exact value for the

primary trigonometric ratios of the angle.

User Ersin Er
by
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1 Answer

5 votes

Answer:


sin(a)=(y)/(r)=-(7√(74) )/(74)


cos(a)=(x)/(r) =-(5√(74) )/(74)


tan(a)=(y)/(x) =(7)/(5)

Explanation:

Given the terminal side of an angle we can calculate the distance between the point given and the origin:


r=√(x^2+y^2)


r=√(|(-5^2)+(-7^2)|)


r=√(74)

y = opposite side

x = adjacent side

r = hypotenuse

Now we have


r=√(74)


x=-5


y=-7


sin(a)=(y)/(r)=-(7√(74) )/(74)


cos(a)=(x)/(r) =-(5√(74) )/(74)


tan(a)=(y)/(x) =(7)/(5)

User Kgd
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