Question

Find the value of common difference 'd' so that:
(2d+1), (2d-1) and (3d + 4) are in AS.​

Answer 1

They are in AP then common difference of successive no. is same

Explanation:

3d+4 -(2d-1) = 2d-1(2d+1)

=> 3d+4-2d+1 = 2d-1-2d -1

=> d+5 = -2

=> d = -2-5

=> d = -7

Hence the value of d is -7