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Solve the compound inequality 1/2 x − 4 < 3 and 7 ≤ 3x + 5.

User Icedtrees
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1 Answer

5 votes


(1)/(2) x - 4 < 3 \\

Add both sides 4


(1)/(2) x - 4 + 4 < 3 + 4 \\


(1)/(2) x < 7 \\

Multiply both sides by 2


2 * (1)/(2) x < 2 * 7 \\


x < 14

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7 \leqslant 3x + 5


3x + 5 \geqslant 7

Subtract both sides minus 5


3x + 5 - 5 \geqslant 7 - 5


3x \geqslant 2

Divide both sides by 3


(3x)/(3) \geqslant (2)/(3) \\


x \geqslant (2)/(3) \\

User Pavel Krymets
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