A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

298,269 views

35 votes

3.6k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

22 votes

Answer:

W = 1/2 K x^2

x^2 = 2 * W / K = 2 * 49 J / (N/m) = .218 / m^2

x = .467 m

Rangooski answered Feb 7, 2022

3.5k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers