A 4600 kg helicopter accelerated upward at 2.0 m/s2. What lift force is exerted by the air on the propellors?

asked Aug 10, 2023 11.3k views

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Answer:

Step-by-step explanation:

let m=4600 kg, a=2.0 m/s2

The lift force(F)=m*(g + a)

=4600*(9.81 + 2)[N]

=54326 N

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