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How many positive integer values of x are solutions to the inequality 10 < -x + 13?

User Alexander Borisenko
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2 Answers

9 votes
9 votes

Answer:

2

Explanation:

We first solve the inequality:

10 < -x + 13

-3 < -x

3 > x.

The only positive integers less than 3 are 1 and 2, for a total of 2 solutions.

User Snakecharmerb
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3.1k points
9 votes
9 votes

9514 1404 393

Answer:

2

Explanation:

The solution to the inequality is ...

10 < -x +13

x < 3 . . . . . . . add x-10 to both sides

The additional restriction that x is positive makes this ...

0 < x < 3

The only integer solutions to this are x = 1 and x = 2.

There are two (2) positive integer values of x that are solutions.

User JohnXF
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2.7k points