Question

I need this please answer

Answer 1

0

Explanation:

`\sin \beta=12/13 \implies \tan \beta=-12/5 \\ \\ \tan(\alpha+\beta)=(\tan \alpha +\tan \beta)/(1-\tan \alpha \tan \beta) \\ \\ =((12/5)+(-12/5))/(1-(12/5)(-12/5)) \\ \\ =0`