101k views
4 votes
Find the equation of the horizontal asymptote of the function f(x)=x^3+1/5x^2-3x^3.

1 Answer

5 votes

Final answer:

The function f(x) = -
2x^3 + 1/5x^2 does not have a horizontal asymptote because the highest degree of x in the polynomial is greater than zero, indicating that the function's value approaches infinity as x approaches infinity.

Step-by-step explanation:

To find the equation of the horizontal asymptote of a function, we look at the behavior of the function as x approaches infinity. For the function f(x) =
x^3 + 1/5x^2 - 3x^3, we must first correct it by consolidating like terms. This gives us f(x) = -
2x^3 + 1/5x^2. In polynomial functions, horizontal asymptotes are determined by the degree of the highest power term in the numerator and the denominator (if any).

Since the highest power of x in f(x) is cubic and there is no denominator (or we can consider the denominator as 1 which is a constant), as x approaches infinity, the function will also approach infinity. Therefore, there is no horizontal asymptote for this kind of polynomial function. A horizontal asymptote would only be present if the highest power of x in the numerator was less than or equal to the highest power of x in the denominator for rational functions.

User Atropo
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories