Question

Hi, can someone please help, and possibly explain the answer please.

Answer 1

`x=(-(-2)\±√((-2)^2-4(3)(0)) )/(2(3))`

Explanation:

Quadratic formula:
`x=(-b\±√(b^2-4ac) )/(2a)` when the equation is
`0=ax^2+bx+c`

The given equation is
`1=-2x+3x^2+1`. Let's first arrange this so its format looks like
`y=ax^2+bx+c`:

`1=-2x+3x^2+1`

`1=3x^2-2x+1`

Subtract 1 from both sides of the equation

`1-1=3x^2-2x+1-1\\0=3x^2-2x+0`

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

`x=(-b\±√(b^2-4ac) )/(2a)\\x=(-(-2)\±√((-2)^2-4(3)(0)) )/(2(3))`

I hope this helps!