Question

5. What is the value of 6(x-2)(x-3) + 4(x-2)(x - 5) when x = -3?

Answer 1

• 340

Explanation:

`\tt 6(x-2)(x-3) + 4(x-2)(x - 5)`

When, x = -3

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To find the value of 6(x-2)(x-3) + 4(x-2)(x - 5), we need to substitute x with -3.

`\tt 6\left(-3-2\right)\left(-3-3\right)+4\left(-3-2\right)\left(-3-5\right)`

`\tt (6)(-5)(-3-3)+4(-3-2)(-3-5)`

`\tt -30\left(-6\right)+4\left(-3-2\right)\left(-3-5\right)`

`\tt -30\left(-6\right)+4\left(-5\right)\left(-3-5\right)`

`\sf -30\left(-6\right)+4\left(-5\right)\left(-8\right)`

`\tt 180+4\left(-5\right)\left(-8\right)`

`\tt 180-\left(-160\right)`

`\tt 180-\left(-160\right)`

`\tt =340`

Therefore, the value of 6(x-2)(x-3) + 4(x-2)(x - 5) is 340!

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Hope this helps!

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