Question

What is an equation of the line that passes through the points (-6,6) and (-3,1)?

Answer 1

y=-
`(5)/(3)`x-4

Explanation:

find the slope m =
`(y2-y1)/(x2-x1)`

m=
`(1-6)/(-3+6)`

m=-
`(5)/(3)`

Use the slope and one of the points to solve for the y-intercept

y1=mx1+b

6=-
`(5)/(3)`(-6)+b

6=10+b

b=6-10

b=-4

plug the values for m and b into y=mx+b

y=-
`(5)/(3)`x-4

Answer 2

y= -1.6x+12

Explanation:

First find the slope.

m=y2-y1 / x2-x1

m= 1-6

-3-(-6)

m=-5

-3+6

m=-5

3

m= -1.6

y-y1=m(x-x1)

y-6= -1.6(x-(-6))

y-6= -1.6x+6

y=-1.6x+12