Answer:Find the equation for a line that passes through (6,4) and has a slope of (-2/3).
Step One: Plug in given values using the slope-intercept form.
x = 6, y = 4, m = (-2/3)
y = m(x) + b
4 = (-2/3)(6) + b
Step Two: Solve for b.
4 = (-2/3)(6) + b
4 = -4 + b
8 = b
Step Three: Plug in values for slope (m) and b (intercept) into the slope-intercept form of a line equation.
y = (-2/3) x + 8